> Hi, > > Can anyone explain to me how hugs manages to derive that > > f x y z = y (y z) x > > is of type > > f :: a -> ((a -> b) -> a -> b) -> (a -> b) -> b
This question was posted from an Oxford University computer; it also smells like homework. If it's genuinely not homework, Lee, I apologise! See http://www.haskell.org/hawiki/HomeworkHelp --KW 8-) -- Keith Wansbrough <[EMAIL PROTECTED]> http://www.cl.cam.ac.uk/users/kw217/ University of Cambridge Computer Laboratory. _______________________________________________ Haskell-Cafe mailing list [EMAIL PROTECTED] http://www.haskell.org/mailman/listinfo/haskell-cafe
