Simon Marlow wrote:
Yes, except that you forgot that not all foreign calls can run
concurrently with Haskell code. Only the "safe" ones can.
Okay, now I understand what is going on. Why is there extra overhead for a 'safe' call?
Keean. // _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
