Because both bit0 and bit1 are free *local* variables within the case expression. So, they have nothing to do with your defined functions bit0 and bit1.
Best regards,
Salvador.
[EMAIL PROTECTED] wrote:
Can a kind soul please enlighten me on why f bit0 and f bit1 both return 0?
bit0 = False
bit1 = True
f x = case x of
bit0 -> 0
bit1 -> 1
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