No, that should work. Haskell equality is not at all like Java equality. In java, '=' basicaly means pointer equality. I am not aware of a way to even make that comparison in Haskell (in general). Haskell '=' behaves a lot more like equals() in Java.
Of course, you mean Haskell '==', as Haskell '=' is declared equality, which is somewhat like '=' in mathematics.
D'oh! Indeed. I mean '==' for Java as well. Java '=' is variable assignment.
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