On 2005-07-07, Henning Thielemann <[EMAIL PROTECTED]> wrote: > My point was that vectors naturally do _not_ represent linear maps at all, > but they are the objects linear maps act on. If I process an audio signal > or an image I can consider it well as vector but why should I consider it > as linear map?
Yes, they do. given a vector "a" in R^n, there are natural, invertible maps co(x): R^n -> R = (a dot x), and scale(b) : R -> R^n = (b * a). These contain all the information in the vector, and do come up naturally in some cases. (Consider a similarity metric on images -- co is a natural one). -- Aaron Denney -><- _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe