2005/8/31, Sebastian Sylvan <[EMAIL PROTECTED]>: > On 8/31/05, Dinh Tien Tuan Anh <[EMAIL PROTECTED]> wrote: > > > > >Something like (untested)... > > > > > >xs <- zipWith ($) forkIO (map (\f -> f x y) funs) > > >tids <- sequence xs > > > > > > > > > what does "zipWith ($)" do ? > > $ is function application, so zipWith ($) will "zip" a list of > functions with a list of arguments, by applying the functions to the > arguments pair-wise, producing a list of results.
But forkIO is function not a list of functions. The above example is incorrect. I think it should be: tids <- sequence [forkIO (f x y) | f <- funs] Cheers, Krasimir _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
