On Tue, Mar 12, 2013 at 3:21 PM, Brandon Allbery <allber...@gmail.com>wrote:
> On Tue, Mar 12, 2013 at 1:52 PM, Carlos Camarao > <carlos.cama...@gmail.com>wrote: > >> Sorry, I think my sentence: >> "To define (+) as an overloaded operator in Haskell, >> you have to define and use a type class." >> is not quite correct. I meant that to define any operator in Haskell you >> have to >> have a type class defined with that operator as member. >> > > What? An operator is just an infix function, taken from the set of > symbols. Any function can be an operator (and is, via `func` syntax). No > typeclass is required to define a random operator. > > What did you really mean to say there? > Sorry, I meant: "To define any _overloaded_ name or operator (i.e. any name/operator that can be overloaded) in Haskell you have to have a type class defined with that name/operator as member. Cheers, Carlos
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