Robert Dockins wrote:
-divides a b = (mod a b == 0)
+divides a b = (mod b a == 0)
Oh, thanks. My program assumed one way to define 'divides' and the
example assumed the other.
When I wrote it I was thinking of (divides a) being a function that
tells me if the input divides 'a'.
Thanks!
Cheers,
Daniel.
--
/\/`) http://oooauthors.org
/\/_/ http://opendocumentfellowship.org
/\/_/
\/_/ I am not over-weight, I am under-tall.
/
_______________________________________________
Haskell-Cafe mailing list
Haskell-Cafe@haskell.org
http://www.haskell.org/mailman/listinfo/haskell-cafe
