Greg Buchholz wrote:
You might also like to try the slightly more efficient...
pyth n = [(a,b,c) | a <- [1..n],
b <- [a..n],
c <- [a+1..n],
a*a + b*b == c*c ]
Cool. I'm amazed that actually works. I've been writing filters upon
filters in all my functions because I didn't realize you could write
things like that.
Cheers,
Daniel.
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