On 2006-01-13 at 16:50EST Robert Dockins wrote: > On Jan 13, 2006, at 4:35 PM, Jon Fairbairn wrote: > > > On 2006-01-13 at 13:32PST Jared Updike wrote: > >> That works except it loses single newline characters. > >> > >> let s = "1234\n5678\n\nabcdefghijklmnopq\n\n,,.,.,." > >> Prelude> blocks s > >> ["12345678","abcdefghijklmnopq",",,.,.,."] > > > > Also the argument to groupBy ought to be some sort of > > equivalence relation. > > Humm, still not reflexive. You need xor.
ugh, yes. How about > > > blocks = map unlines > > . filter (all $ not . null) > > . groupBy (\a b -> null b == null a) > > . lines ? -- Jón Fairbairn Jon.Fairbairn at cl.cam.ac.uk _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe