Mathew Mills <[EMAIL PROTECTED]> writes: > Is there anything that can be done (easily) to reduce the rounding errors?
The hint that I gave before is one easy way. > fib :: Integer -> Integer > fib x = let phi = ( 1 + sqrt 5 ) / 2 > in truncate( ( 1 / sqrt 5 ) * ( phi ^ x + 0.5) ) You run out of precision eventually. IEEE Double's give you about 15 decimal digits, so the results become approximate for x > 75. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
