Szymon Ząbkiewicz wrote:
Hi.
When trying to compilke this code:
{...}
8.if (a == 0) && (b == 0)
9. then do
10. nr1 <- read (prompt "enter 1. number: ")
11. nr2 <- read (prompt "enter 2. number: ")
The nr2 here is not passed to the rest of the do block started on line 9
12. else do
13. let nr1 = a
14. nr2 = b
The nr1 and nr2 in the else block have absolutely nothing to do with the nr1 and
nr2 from the then block. The names are the same, but that does not make them
the same as they could be totally different types.
{...}
The compiler tells me thats there's an error on line 10:
"The last statement in a 'do' construct mesy be an expression"
Could you tell me how to change it so that the "declaration" of the
first nr1 and nr2 is still in the "then" block.
The "x <- foo" syntax is not a declaration.
Also, the type of "read" is String->a which is NOT a monad type, so I will fix
that as well:
One could do this:
(nr1,nr2) <- if (a==0) && (b==0)
then do a' <- liftM read (prompt "...")
b' <- liftM read (prompt "...")
return (a',b')
else return (a,b)
The ghc compiler is usually smart enough to remove the tuple (,) construction
from the code.
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