Hi
func2 f g l = filter f (map g l) is func2p f g = (filter f) . (map g)
func2 = (. map) . (.) . filter Again, how anyone can come up with a solution like this, is entirely beyond me... Thanks Neil _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
