Bertram Felgenhauer wrote:
This is correct according to the IEEE 754 standard, which defines that NaN compares unequal to everything, including itself.
This is numerically useful, perhaps, but nonetheless disturbing. For it would be helpful to expect that any type that presumes to be an instance of Eq has a == a = True.
There really are two different notions of equality here. Perhaps they should be given two different names in the language?
-- Ashley Yakeley Seattle, WA _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
