> It makes good sense. Each list will of events will be evaluated > lazily, so thing will appear there as they appear in the input.
Indeed, thankyou. On a closer inspection I can in fact see that although the first value, (chn,[msgs]), will never appear, one can nonetheless start reading the [msgs] of any channel, precisely because they are in order in the input. Apologies for the noise, slowly learning... Regards, Rohan _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
