Hello,
I just tripped over the "Contexts differ in length" error message. I know it's not a new problem, but I thought I'd enquire as to its status.
I have run into that a number of times. There aren't any technical issues with solving it, in fact, depending on how one implements the type checker, it is more work to implement this extra restriction (Hugs and THIH don't impose this restriction). The basic idea is that we check values with explicit signatures after we have finished type inference. While we do type inference we may simply assume that the values have their specified types. It is proposed for fixing in Haskell' but I was surprised that it did not seem to appear on the "definitely in" list (as far as I can recall---I might be wrong). Hopefully the report will be fixed though. Otherwise, as Ian mentioned, it works in GHC 6.6 with -fglasgow-exts. Also, there should be no problems with higher-ranked types etc. -Iavor On 11/29/06, Conor McBride <[EMAIL PROTECTED]> wrote:
For those of you who haven't seen it, here's an example, contrived but compact. > data Thing > = Val Int > | Grok Thing (Maybe Int -> Int) > eval :: Monad m => Thing -> m Int > eval (Val i) = return i > eval (Grok t f) = return (f (eval t)) My eval function compiles ok. See? The recursive call to eval targets the Maybe monad, so I get *Mmm> eval (Grok (Val 5) (maybe 0 (1 +))) :: Maybe Int Just 6 However, when I try to decompose eval as a pair of mutually recursive functions, namely > foo :: Monad m => Thing -> m Int > foo (Val i) = return i > foo (Grok t f) = return (goo t f) > goo :: Thing -> (Maybe Int -> Int) -> Int > goo t f = f (foo t) I get Mmm.lhs:15:1: Contexts differ in length When matching the contexts of the signatures for foo :: forall (m :: * -> *). (Monad m) => Thing -> m Int goo :: Thing -> (Maybe Int -> Int) -> Int The signature contexts in a mutually recursive group should all be identical Poking about on the web, I got the impression that this was a known infelicity in ghc 6.4 (which I'm using), due to be ironed out. However, an early-adopting colleague with 6.6 alleges that foo-goo is still poisonous. I'm wondering what the story is. I mean, is there some nasty problem lurking here which prevents the lifting of this peculiar restriction? I'm not in a panic about this. I have a workaround for the problem as I encountered it in practice. Mind you, it's the sort of thing that's likely to happen more often, the more you localise the effects you tend to use. In the above, goo doesn't throw exceptions; rather, because goo has a handler, it can offer a /local/ exception-throwing capability to foo. Curious Conor _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
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