Hi,
I'm reading the Haskell school of expression by Paul Hudok. Great book.
However I would like some feedback about a solution to an exercise
The problem is quite simple :
define f1 and f2 (using higher order functions ) such that
f1 (f2 (*) [1..4]) 5 => [5,10,15,20]
I have come up with the following solution :
f2 :: (a->b)->[a] -> [b]
f2 f xs = map f xs
f1 fs a = map (applyOp a) fs
applyOp b f = f b
But I guess there must be some more elegant way. f2 isn't at all
original.
And the applyOp sounds silly.
Any comments or suggestions are welcome.
thanks,
Pieter
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