Can anyone explain the following behavior (GHCi 6.6):
Prelude Control.Monad.ST> runST (return 42) 42 Prelude Control.Monad.ST> (runST . return) 42 <interactive>:1:9: Couldn't match expected type `forall s. ST s a' against inferred type `m a1' In the second argument of `(.)', namely `return' In the expression: (runST . return) 42 In the definition of `it': it = (runST . return) 42 Thanks, Yitz _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe