Hi
That's not quite what I was trying to say. (p^~p)->q is equivalent to _|_ in the sense that once you derive/compute (respectively) it, the "world" in which it exists breaks.
I think thats a bit overly harsh view of _|_ to take. The world does not break once you compute _|_ - a _|_ value doesn't allow you to prove/compute anything you couldn't before. While removing _|_ from the language does make some things nicer to reason about, there aren't many corners where _|_ really gets in the way that much - seq being one of those few corners. Thanks Neil _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
