On Tue, May 29, 2007 at 11:20:27AM +0100, David House wrote: > On 29/05/07, Daniel McAllansmith <[EMAIL PROTECTED]> wrote: > >Just in case there was some sort of miscommunication, the actual answer to > >your question is (/=) :: a -> a -> Bool, as Neil said. > > Almost, (/=) :: Eq a => a -> a.
Almost again! (/=) :: Eq a => a -> a -> Bool Best regards Tomek _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
