> > What is the basic philosophy for Bool being a member of Ord? > What justifies False < True?
The implication ordering, which on this smallest non-trivial Boolean algebra happens to be a linear order, is therefore the natural candidate for Ord, the type class of ``default linear orders''. False ==> True Wolfram _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
