You hardly ever need to use explicit recursion in Haskell. Every
useful way of doing recursion has already been captured in some
higher order function. For example here is your subarrays
implemented using unfoldr:
subarrays xs = concat $ unfoldr f xs
where
f [] = Nothing
f xs = Just ( [ys | n <- [1..length xs], ys <- [(take n
xs)]], tail xs)
On Jul 17, 2007, at 4:26 PM, James Hunt wrote:
Hi,
As a struggling newbie, I've started to try various exercises in
order to improve. I decided to try the latest Ruby Quiz (http://
www.rubyquiz.com/quiz131.html) in Haskell. Would someone be kind
enough to cast their eye over my code? I get the feeling there's a
better way of doing it!
subarrays :: [a] -> [[a]]
subarrays [] = [[]]
subarrays xs = (sa xs) ++ subarrays (tail xs)
where sa xs = [ys | n <- [1..length xs], ys <- [(take n xs)]]
maxsubarrays :: [Integer] -> [Integer]
maxsubarrays xs = msa [] (subarrays xs)
where
msa m [] = m
msa m (x:xs)
| sum x > sum m = msa x xs
| otherwise = msa m xs
--for testing: should return [2, 5, -1, 3]
main = maxsubarrays [-1, 2, 5, -1, 3, -2, 1]
I've read tutorials about the syntax of Haskell, but I can't seem
to find any that teach you how to really "think" in a Haskell way.
Is there anything (books, online tutorials, exercises) that anyone
could recommend?
Thanks,
James
_______________________________________________
Haskell-Cafe mailing list
Haskell-Cafe@haskell.org
http://www.haskell.org/mailman/listinfo/haskell-cafe
___________________
(---o-------o-o-o---o-o-o----(
David F. Place
mailto:[EMAIL PROTECTED]
_______________________________________________
Haskell-Cafe mailing list
Haskell-Cafe@haskell.org
http://www.haskell.org/mailman/listinfo/haskell-cafe