| f (g (<- mx)) | | does this stand for | | (a) mx >>= \x-> f (g x) | (b) f (mx >>= \x-> (g x)) | (c) none of the above, because there's no do | (d) something else entirely
For me the answer is definitely (c). Furthermore there must be no lambda between the "monadic splice" and the "do". Given that, I think the meaning of a monadic splice is straightforward, and all your excellent questions have easy answers. The question remains of whether or not it's valuable. Simon _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
