On 8/3/07, Neil Mitchell <[EMAIL PROTECTED]> wrote:
This is how I understand it:
> Can you use (<-) outside of a do block?
> b >> f (<- a)
b >> do { ta <-a; f ta }
or
b >> a >>= \ta -> f ta
> What are the semantics of
> do b >> f (<- a)
do b >> a >>= \ta -> f ta
> Given:
>
> if (<- a) then f (<- b) else g (<- c)
a >>= \ta -> if (ta) then ( b >>= \tb -> f tb ) else ( c >>= \tc -> f tc )
> do let x = (<- a)
> f x
No idea if that could be possible. or maybe :
do a >>= \ta -> let x = ta in f x
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