rodrigo.bonifacio wrote:
instance Eq Step where
Step id1 scenario1 action1 state1 response1 == Step id2 scenario2 action2 state2 response2 = id == id
_ == _ = False
Almost. You just used 'id' and 'id' when you meant 'id1' and 'id2'.
> instance Eq Step where
> Step id1 scenario1 action1 state1 response1 == Step id2 scenario2
action2 state2 response2 = id1 == id2
but it's a common idiom not to bother to name unused parameters, so:
> instance Eq Step where
> Step id1 _ _ _ _ == Step id2 _ _ _ _ = id1 == id2
(and the default case is never reached so you don't need it)
ps.: sorry, this kind of basic question can be sent to this list?
Yes, that's fine.
You may get quicker answers if you hop onto IRC at #haskell, though.
Jules
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