On Mon, 2007-09-03 at 19:47 +0200, Lars Oppermann wrote: > Dear all, > > In the Haskell Wiki at http://www.haskell.org/haskellwiki/Closure > there is an example for a function returning a closure given as > f x = (\y -> x + y) > > Another way to achieve the same effect would be to write > f' x = (+) x > > which to me as a beginner looks somewhat like pointfree style. > > Would f' be considered to return a closure
Going backwards: Yes. The pointfree "solution" in this case would simply be f' = (+) Note that f x = \y -> x + y is written that way for emphasis and is identical to f x y = x + y _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
