On Thu, Sep 20, 2007 at 04:17:54AM +0100, PR Stanley wrote: > Hi > length = foldr (. n . 1 + n) 0 > Any idea how to define length with foldr. The above definition doesn't make > much sense. > Many thanks, Paul
length = foldr (λ_ n → 1 + n) 0 or, in ASCII concrete syntax length = foldr (\_ n -> 1 + n) 0 Stefan
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