a good sanity check for saneness of two fxs is to "quickcheck" them, as I
believe I provided an example to for a previous question of yours.
Though I think in this case that's impossible because, as someone else
pointed out, not even the function tyes agree.
t.
PR Stanley <[EMAIL PROTECTED]>
Sent by: [EMAIL PROTECTED]
10/15/2007 06:56 PM
To
[email protected]
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Subject
[Haskell-cafe] Equality Question
Hi
is const = id?
const 'x' 'y'
'x'
id 'x'
'x'
Cheers,
Paul
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