On Wed, 2007-11-14 at 16:27 -0800, Justin Bailey wrote: > It's: > > f $! x = x `seq` f x > > That is, the argument to the right of $! is forced to evaluate, and > then that value is passed to the function on the left. The function > itself is not strictly evaluated (i.e., f x) I don't believe.
Application is strict so f is forced and id is strict so f x is forced. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
