On 14 Nov 2007, at 4:32 PM, Shachaf Ben-Kiki wrote:
On Nov 14, 2007 4:27 PM, Justin Bailey <[EMAIL PROTECTED]> wrote:
It's:
f $! x = x `seq` f x
That is, the argument to the right of $! is forced to evaluate, and
then that value is passed to the function on the left. The function
itself is not strictly evaluated (i.e., f x) I don't believe.
Unless you mean f -- which I still don't think would do much -- it
wouldn't make sense to evaluate (f x) strictly.
Right. (f x) evaluates f and then applies it to x. (f $! x)
evaluates x, evaluates f, and then applies f to x.
jcc
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