On Nov 28, 2007 12:12 PM, Kalman Noel <[EMAIL PROTECTED]> wrote: > Sebastian Sylvan: > > primes :: [Integer] > > primes = 2 : filter (null . primeFactors) [3,5..] > > > > primeFactors :: Integer-> [Integer] > > primeFactors n = factor n primes > > where > > factor m (p:ps) | p*p > m = [] > > | m `mod` p == 0 = p : factor (m `div` p) (p:ps) > > | otherwise = factor m ps > > Your definition gives a strange meaning to primeFactors. I'd want that for all > n, product (primeFactors n) == n. I think this law holds for the code posted > by Olivier.
Yes you're right. That is property should clearly hold. -- Sebastian Sylvan +44(0)7857-300802 UIN: 44640862 _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe