Hello all,
It is either too difficult to get two integers of a bytestring, in
which case something should be done to ease the process or I should
learn much more Haskell. I guess the latter is the correct guess.
I have a bytestring containing two naturals. I was to get them as
efficiently as possible. Here's my code:
parseHeader :: BS.ByteString -> (Int, Int)
parseHeader bs =
let first = BS.readInt $ BS.dropWhile (not . isDigit) bs
in
if(isNothing first)
then
error "Couldn't find first natural."
else
let second = BS.readInt $ BS.dropWhile (not . isDigit) $
snd $ fromJust first
in
if(isNothing second)
then
error "Couldn't find second natural."
else
(fst $ fromJust first, fst $ fromJust second)
This seems to work:
> parseHeader $ BS.pack "hello 252 359"
(252,359)
Is there a better way?
Cheers,
--
Paulo Jorge Matos - pocm at soton.ac.uk
http://www.personal.soton.ac.uk/pocm
PhD Student @ ECS
University of Southampton, UK
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