Achim Schneider <[EMAIL PROTECTED]> writes: >> You need to use the / operator, if you want to do floating-point >> division.
> Yes, exactly, integers don't have +-0 and +-infinity... only > (obviously) a kind of nan. No, failure (exception, bottom) is different from NaN, which is just another value in the domain - admittedly one which behaves rather strangely. > Said differently: I don't know a thing about floats or numerics. Perhaps it helps to think of floating point values as intervals? If +0 means some number between 0 and the next possible representable number (and similar for -0), it may make more sense to have 1/+0 and 1/-0 behave differently. -k -- If I haven't seen further, it is by standing in the footprints of giants _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
