Consider the function cond x y z = if x then y else z
I guess we can certainly say cond is strict in x. But what about y and z? If x is true, then cond is strict in y If x is false, then cond is strict in z So we can't really say cond is lazy nor strict in its second or third argument. Of course, this is the case for many more functions, but in the case of the if-then-else primitive, does the strictness analyzer make use of this "mutually exclusive strictness" fact? Cheers, Peter _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
