> tricky 0 = constant 0
> tricky d = add e0 e1
> where
> (e0, e1) = fork (tricky (d-1))
Oops, I just realised that this isn't a very good example of
expressible sharing! The problem is that it doesn't take any inputs,
and expressible sharing just collapses (partially evaluates) operators
when they are applied to constants. A better example would be
something that takes an input, such as
distrib a [] = []
distrib a (x:xs) = (a0, x) : distrib a1 xs
where
(a0, a1) = fork a
Matt.
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