Thanks, Bulat, I'll look into this!
On 2/23/08, Bulat Ziganshin <[EMAIL PROTECTED]> wrote: > Hello Uwe, > > > Saturday, February 23, 2008, 11:35:35 PM, you wrote: > > >> mysighandler = > >> Catch (do hPutStrLn stderr "caught a signal!" > >> fail "Interrupt!") > > > > scheme calculation doesn't get interrupted at all! I see in the > > System.Posix.Signals documentation that the signal handler gets > > invoked in a new thread; is this the source of the problem? > > > yes, fail kills only this thread :) > > you should store thread id of thread running interpreter and send > async exception to it. control.concurrent is probably contains all > required functions > > > > -- > Best regards, > Bulat mailto:[EMAIL PROTECTED] > > _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
