On Mon, Mar 10, 2008 at 11:11 PM, Paulo J. Matos <[EMAIL PROTECTED]> wrote:
>  outputLines i = mapM (putStrLn . show) (take i $ iterate ((+) 1) 1)
>
>  However, this is in fact
>  outputLines :: Int -> IO [()]

As others suggested you can use mapM_

Furthermore, you can simplify it a bit with some syntactic sugar

outputLines i = mapM_ (putStrLn . show) [1..i]

BTW, considering how often is (putStrLn.show)  used, it is surprising
that there is no Ln variant for print (just like it happens with
putStr and putStrLn)
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