Thanks, I'd thought it was something to do with incompatible types. I can now create a simpler problem:
tester2 = reserved "parameter" <|> symbol ":" Certainly I could use reserved ":" instead of symbol, but where is my thinking with symbol here going wrong? Surely the above example isn't so odd? Paul -----Original Message----- From: Luke Palmer [mailto:[EMAIL PROTECTED] Sent: Fri 3/28/2008 12:26 AM To: Paul Keir Cc: haskell-cafe@haskell.org Subject: Re: [Haskell-cafe] Parsec Expected Type Hi Paul, 2008/3/27 Paul Keir <[EMAIL PROTECTED]>: > Hi, > > Does anyone know why this reduced Parsec production stops compilation, and > how I can fix it? > > tester = reserved "parameter" > <|> do { reserved "dimension"; symbol ":" } Look at the types of "reserved" and "symbol" (from http://www.haskell.org/ghc/docs/latest/html/libraries/parsec/Text-ParserCombinators-Parsec-Token.html): symbol :: String -> CharParser st String reserved :: String -> CharParser st () The type of a do block is the same as the type of its last statement. But (reserved "parameter") and (symbol ";") do not have the same type. Luke
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