Re: [Haskell-cafe] The range operator

[Roel van Dijk]

On Fri, Apr 4, 2008 at 10:49 PM, Andrew Coppin
<[EMAIL PROTECTED]> wrote:
>  More to the point, the range y..z goes in steps of y-z. ;-)
[x,y..z] goes in steps of y-x ;-), [y..z] goes in steps of 1
(depending on the type).
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