On Sun, Nov 30, 2008 at 9:30 AM, Luke Palmer <[EMAIL PROTECTED]> wrote: > cross :: [a] -> [b] -> [(a,b)] > > It's just kind of a pain (you build [(a,(b,(c,d)))] and then flatten > out the tuples). The applicative notation is a neat little trick > which does this work for you.
It seems to me like this would all be easy if (a,b,c,d) was sugar for (a,(b,(c,d))), and I can't see a disadvantage to that. --Max _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
