Daniel Peebles ha scritto:
As far as I know, the reason for this is that the UIO instance for productions writes the two "rows" out sequentially to file, but doesn't include any means to determine the length of the two halves when it's loading up again. When you try to read the production back in, it tries to read in two arrays, but the first array read consumes all the input leaving the second with nothing.
Ok, thanks. For now, I think that the simple solution is to not use UArr (a:*:b), but (UArr a, UArr b). Or I should just switch to Data.Array.Unboxed. The operations I need with the array are only: - sum of elements - binary search - serialization/deserialization - sorting (but right now I sort the list before creating the array) with a very big data set. For my problem, is uvector the best solution? What about storablevector or cvector, instead? Regards Manlio _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
