Creighton Hogg schrieb: > Okay, so I think what you want is > > [...]
Yes. Your solution works. Thank you. But: > a <- msum . map return $ [1,2,3] Why Do I need this "msum . map return" thing? The "map return" part is somewhat clear. But not entirely. Which type of monad is created here? The msum-part ist totally confusing me: First we create a list with some monads (?) and then msum them? What is going on there? > first, that you tried to use literal list syntax in > do notation which I believe only works in the actual [] monad. Is the "x <- xs" in the list monad a form of syntactic sugar? > Second, you didn't have the runListT acting on > the foobar, which is how you go from a ListT IO Int to a IO [Int]. Ah, yes. This point I understood now. Thank you again. Michael _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
