Günther Schmidt wrote:
data Container a = Single a | Many a [a] but the problem above is that the data structure would allow to construct a Many 5 [] :: Container Int.
I think you meant to do either data Container a = Single a | Many a (Container a) or data Container a = Container a [a] - Jake _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe