ghci> map reverse $ foldM (\answer list -> [x:answer | x <- list, not
$ x `elem` answer]) [] [[2,3], [1,2], [2,3,4], [1,2,3]]
[[2,1,4,3],[3,1,4,2],[3,2,4,1]]
On 14 Jun 2009, at 12:06, Fernan Bolando wrote:
Hi all
If I have a number of list
example
list1 = [2,3]
list2 = [1,2]
list3 = [2,3,4]
list4 = [1,2,3]
I want to create a list from the list above with n elements,
non-repeating and each elements index represents 1 of the elements
from the corresponding list so for the above input I would get.
a = [3,2,4,1]
ofcourse there may be several set that will satisfy the problem, so a
list of list that satisfies would be good.
How do I do this in haskell? or is there a code snippet that seems to
work similarly?
thanks
fernan
--
http://www.fernski.com
_______________________________________________
Haskell-Cafe mailing list
Haskell-Cafe@haskell.org
http://www.haskell.org/mailman/listinfo/haskell-cafe
_______________________________________________
Haskell-Cafe mailing list
Haskell-Cafe@haskell.org
http://www.haskell.org/mailman/listinfo/haskell-cafe
