I don't know, but:
number
-- definition
= do { num <- natural ; return $ num }
-- desugar
= natural >>= \num -> return $ num
-- apply ($)
= natural >>= \num -> return num
-- eta elimination (f == \x -> f x)
= natural >>= return
-- monad law
= natural
(modulo monomorphism restriction, since number doesn't take any arguments
and doesn't have a type signature)
-- ryan
On Tue, Sep 29, 2009 at 12:54 AM, Anatoly Yakovenko
<aeyakove...@gmail.com>wrote:
> number = do { num <- natural
> ; return $ num
> }
> main = do
> txt <- hGetContents stdin
> print $ parse number "stdin" txt
>
>
> why doesn't that work?
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