On Wed, Oct 7, 2009 at 12:08 PM, Ben Franksen <ben.frank...@online.de> wrote: > > More generally, any ring with multiplicative unit (let's call it 'one') will > do.
Isn't that every ring? As I understand it, the multiplication in a ring is required to form a monoid. -- Dave Menendez <d...@zednenem.com> <http://www.eyrie.org/~zednenem/> _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
