Hello zaxis, Thursday, October 22, 2009, 1:03:21 PM, you wrote:
> Is [(1,1),(2,2),(3,3)] been regarded as a hash ? If not, what is the best > way to change it to [(1,1),(2,2222),(3,3)] in function `f` ? f = map (\x@(a,b) -> if a==2 then (a,2222) else x) or f xs = [(a, if a==2 then 2222 else b) | (a,b) <- xs] but anyway, modifying one value inside complex datastructure is not FP way. you should consider writing a function that maps your entire input data to output one -- Best regards, Bulat mailto:bulat.zigans...@gmail.com _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
