Eduard Sergeev wrote: > > The former passes three-argument function 'step' to foldr and the later > passes two-argument function which is the result of the partial > application (step f). >
Correction :) 4-arg and 3-arg respectively. -- View this message in context: http://old.nabble.com/foldl-in-terms-of-foldr-tp27322307p27325593.html Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com. _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
