Newbie trying to get through Bird. Could someone provide a clean solution,
with proof (so I can see how these proofs are laid out), to this:
Given:
f :: Integer -> Integerg :: Integer -> (Integer -> Integer)
h :: ...h x y = f (g x y)
Questions:
a. Fill in the type assignment for "h".
b. Which of the following is true: (i) h = f . g (ii) h x = f . (g
x) (iii) h x y = f . (g x y)
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