I wrote: >> keep :: ((t -> b) -> u -> b) -> ((t1 -> t) -> b) -> (t1 -> u) -> b >> so then >> nameZip = keep (drop' . drop') names
Günther Schmidt wrote: > don't be tease man, show me what you got :) Ivan Miljenovic wrote: >> Methinks Yitzchak made a typo Yes, sorry about that. Tested in ghci this time :). keep :: (forall c . (t -> c) -> u -> c) -> ((t1 -> t) -> b) -> (t1 -> u) -> b keep transform rec = \fn -> rec $ transform id . fn Regards, Yitz _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
